0=2x^2-13x+36

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Solution for 0=2x^2-13x+36 equation: 



0=2x^2-13x+36

We move all terms to the left:

0-(2x^2-13x+36)=0

We add all the numbers together, and all the variables

-(2x^2-13x+36)=0

We get rid of parentheses

-2x^2+13x-36=0

a = -2; b = 13; c = -36;
Δ = b2-4ac
Δ = 132-4·(-2)·(-36)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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